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Can You Remember How You Did It? - Andromedean Transmissions!

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Didymos

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Can You Remember How You Did It? - Andromedean Transmissions!

Post  Didymos on Fri Oct 19, 2012 6:49 am

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Transmissions from Andromeda


SuiGeneris on Thu Apr 15, 2010 12:46 am






























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Re: Can You Remember How You Did It? - Andromedean Transmissions!

Post  Didymos on Fri Oct 19, 2012 6:51 am

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Re: Transmissions from Andromeda


SuiGeneris on Thu Apr 15, 2010 12:47 am





















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Re: Can You Remember How You Did It? - Andromedean Transmissions!

Post  Didymos on Fri Oct 19, 2012 6:53 am

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Re: Transmissions from Andromeda


SuiGeneris on Thu Apr 15, 2010 12:49 am














Transmissions from Andromeda by
GrandPa Abaloun and GrandMa Balouna

and delegated to Xeia as Ambassadora from the Council of Andromeda
for the Sirian Ambassadors then delegated to contact the 3D-Thuban Council
of the Serpentina constituency of the Gaian Realm.


This post has been edited by anubis on Apr 1 2010, 06:17 AM


--------------------

NAME ABALOUN =THE FREEDOM= BALOUNA AMEN
THE MAGIC NAME=33+33+33=99=THE THUBAN
FREEDOM=ANUBIS=66=ABRAXAS=WOMAN=NAME AMEN

"Because of a great love, one is courageous" Lao Tzu
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Re: Can You Remember How You Did It? - Andromedean Transmissions!

Post  Didymos on Sat Oct 27, 2012 10:31 am



A perhaps simpler way to understand the relativity of time and velocity

Hi April!

The X' refers to coordinate systems and not to any calculus. There is no calculus in this post, except as basic differential and the difference between two measurements.

Two events, say the sending and receiving of a signal are measured in TWO reference systems O and O' say with reference frame O moving with velocity v relative to reference frame O' or vice versa.

Much confusion then arises in failing to properly define the coordinates in a manner of 'who moves relative to what'.

So, a 'proper time' can be defined in either system; 'proper' meaning that the events coincide in whatever reference frame thus defined - they have the same locality and the measurements are taken at the same place. Then relative to that frame an 'improper' time results in the quandaries (or illogicalities wrt common sense) of Special Relativity. The 'improper' time is measured at different places.

So in the example both April's time and Mac's time can be the 'proper' time and be 'dilated' relative to the other under the coordinate definitions.

But this is used technically to define instantenuity and simultaneity in the Lorentz formulas, which I tried to derive from a more simple premise, using the geometric mean of differentials.

Tony B.


Three Larrikins, whom we may name April, Mac and John decided once upon a time to test a fundamental premise of Special Relativity and the measurement of time.

They hired a chaffeur-driven limousine of say 4 meters in length and defined a coordinate system for that limousine centred at its midpoint (x,y)=(0,0).

The limousine would travel due East with Mac positioned at a coordinate 1 meter to the West at (x,y)=(-1,0) facing towards the East. John would face to the West, opposite Mac at a coordinate (+1,0). Mac and John would then remain stationary for the duration of the experiment and precisely 2 meters apart with a so equidistant lightsource at the centre.
The limousine would travel at a speed v, say 80 km/h from the West and past April, positioned due South at a coordinate (0,-3).

The larrikins now decide to label the event A to be the precise instant for the centre of the limousine to be coincident with the y=0 coordinate for the stationary April. Precisely at that instant,
the lightsource would switch on and send an omnidirectional lightsignal to the measuring instruments of the three larrikins.

Both, Mac and John now define the event B to be the reception of the signal. As both Mac and John are stationary relative to each other the lightpath x=ct will be identical, if the postulates of Special Relativity hold.

In particular, the time measured should be the same as tMac=tJohn=x/c=1/c seconds.
Their positional coordinates also remain unchanged at xMac=-1 and xJohn=+1 relative to their stationary frame of reference within the limousine.

But the situation is not as clear for April.
She sees the limousine travelling past her at speed v; which changes the lightpath. April actually postulates, that she will observe Mac to receive the lightsignal before John; because the light must travel further to get to John's photo receptor, than to Mac's.

So April measures two events B in say: B1Mac and B2John.

The lightpath becomes ambiguous in x'John=(c+v)t'John and x'Mac=(c-v)t'Mac and due to a simple Galilean coordinate transformation or 'shifting of the x-axis' and for an apparent 'addition of the velocities'.

April postulates a first approximation for her measurement of the B event in deriving:
t'John=x'John/(c+v)=x'John(1/c)/(1+v/c)=x'JohntJohn/(1+v/c) and t'Mac=x'Mac/(c-v)=x'Mac(1/c)/(1-v/c)=x'MactMac/(1-v/c).


April then takes the geometric mean of her B events to get a second approximation in:

tApril=√(t'John.t'Mac)=√{x'John.x'Mac(1/c2)/(1-(v/c)2)}.

But (1/c2)=(tJohn.tMac)/(xJohn.xMac) as the lightpath relative to the limousine and with tJohn=tMac for the expression:

tApril=tMac.√[x'Mac.x'John/xMac.xJohn]/√(1-(v/c)2).


April's second approximation so begins to crystallise relativistic time dilation in proper time tMac=tJohn and c-invariance xMac=x'Mac and xJohn=x'John for relative reference frames.

The xB1Mac coordinate becomes xApril1=(-1+v/c)/√(1-(v/c)2) and the xB12John coordinate becomes xApril2=(+1+ v/c)/√(1-(v/c)2) as the Lorentz-Coordinate transformation for displacement.

This is generalised as: X'=(X-VT)/√(1-(V/c)2) for two reference frames O and O' moving relative to each other at a speed V.

Also the Lorentz-Contraction appears in the proper length being xApril and the contracted length becoming ±1+v/c relative the two Aprillean measurements.

The Lorentzian time coordinates transform similarly in adding a v.x/c2 term to the proper time in the time dilation expression.

T'=(T-VX/c2)/√(1-(V/c)2).

April's precise measurement, so would give the results:

tApril1=(1/c-v/c2)/√(1-(v/c)2)=(1/c)√{(1-v/c)/(1+v/c)} and tApril2=(1/c+v/c2)/√(1-(v/c)2)=(1/c)√{(1+v/c)/(1-v/c)}.

One can now see, that tApril1=tMac√{(1-v/c)/(1+v/c)}< tMac
and that tApril2=tMac√{(1+v/c)/(1-v/c)}> tMac for all velocities vMac=tJohn.

As the second measurement gives the relative time measurement for the lightpath with respect to John however; April observes the time taken for the light signal to reach John as being longer than that for travelling to Mac by the time differential:

tApril2-tApril1= tMac{√[(1+v/c)/(1-v/c)]-√[(1-v/c)/(1+v/c)]}.

In our example of a speed of 80 km/h or 22.22..m/s; this time difference calculates as about:
(1.000000074..- 0.999999925..)/c~ 0.00000015/c seconds or so 0.5 femtoseconds (10-15).


One can obtain the time dilation formulation by simple geometry in postulating April to receive the lightsignal at the instant the coordinates for the moving limousine to coincide as the origin in x=y=0.

This means, that the lightpath is 'pythagorised' in Mac sending a signal when the limousine's origin is at x=-vt and John receives Mac's signal for the origin to have moved to x=+vt.

A stationary limousine so would define a lightpath for April of 2y=ct (or 6 meters in our example), being the return trip of the signal from the source to April and back again. Here t is a proper time, measured in a stationary reference frame.

The moving limousine vectorises as y and vt' with t' here being the improper time for a lightpath of
[½ct']2=[½ct]2+[½vt']2.

Solving for t' gives: t'=√{(c2t2/(c2-v2)}=t/√{1-(v/c)2} and which is the time dilation formula of Special Relativity.




Relative Velocity


Much confusion exists for the general reader, when attempting to apply Special Relativity to velocity concepts.
Using the above we shall here try to simplify the scenario in considering three cases.


Case A: A rocket moves away from the earth at relativistic speed and fires a projectile also at relativistic speed, relative to itself. What is the projectiles speed relative to the earth?

Case B: Two rockets approach each other and collide at relativistic speeds as measured on the earth. What is the relative speed of the centre of mass of the system or what is the velocity of the first rocket relative to the second rocket?

Case C: Two rockets travel parallel at relativistic speeds as observed on the earth. What is the relativistic speed of the centre of mass?


Generally, the Lorentz transforms gave the coordinate transformas for displacement and for time. One now differentiates dX'/dT'=U'x in the differentials or one simply defines:

U'x= X'/T'=[(X-VT)/√(1-(V/c)2)]/[(T-VX/c2)/√(1-(V/c)2)].

Dividing the expression by T in numerator and denominator gives:

U'x=[X-VT]/[T-VX/c2]=[Ux-V]/[1-VUx/c2].


Here U'x depicts the velocity in reference frame O' and Ux represents the velocity in frame O with V the velocity relative to the moving frames. The velocity V can be said to be a relative velocity of a third 'particle', measured in the two reference frames. V is positive in the the +x direction and negative in the opposite.

If we use the inverse Lorentz transformation (exchanging indices and replacing V by -V), then the symmetry of the postulates of Special Relativity gives Ux=[U'x+V]/[1+VU'x/c2]. (Solving algebraically gives of course the same result).


It is advisable to use this formulation in cases such as Case A, where the moving frame relative to earth superposes another moving frame.



Case A:

We choose the rocket to move at 0.8c relative to the earth and emitting a projectile in the forward motion at 0.4c.

In this example U'x=0.8c in frame O' and as the projectile moves relative to this frame at 0.4c, the frames move relative to each other at this speed V=0.4c. We seek the relative velocity of the 'particle' relative to the other frame O that is velocity Ux.

Galilean Relativity would say the projectile moves at 1.2c relative to the earth; but our expression above cannot ignore the denominator and we get:


U'x=[1.2c]/[1+0.32]=0.9091c.

No relative velocity can ever exceed the speed of light.



Case B:

We choose a rocket A moving to the right at 0.8c and the rocket B moving to the left at 0.6c as measured in the earthframe O. This situation must also add the velocities as in the classical Galilean case for collinear collisions.

We seek the velocity of rocket A relative to frame O', labelling rocket A as the 'particle' with velocity Ux relative to the earth.


Then Ux=0.8c and V=-0.6c in frame O for U'x=1.4c/[1.48]=0.9459c as the velocity of the centre of mass or as the velocity of rocket A as measured by rocket B in its reference frame O' (relative to itself at rest).

Reassigning the frames in seeking the relative velocity of rocket B relative to rocket A gives the same result in a varied numeracy. Here Ux=0.8c in frame O of rocket A and

U'x=-0.6c=[0.8c-V]/[1-0.8V/c] in frame B and the earth observer becomes the 'particle' with relative frame velocity V.

Solving for V=1.4c/1.48 via -0.6c+0.48V=0.8c-V gives the previous result, now for V.


Case C:

This case simply subtracts the velocities. We choose rocket A to move right at 0.8c and superpose rocket B moving also to the right at 0.6c. A classical Galilean transform would predict a relative speed of 0.2c between the rockets.

Let Ux=0.8c in O and seek U'x in O' i.e the velocity of rocket A relative to rocket B.

U'x=[0.8c-0.6c]/[1-0.48]=0.3846c.

Also, 0.6c=[0.8c-V]/[1-0.8V/c] for 0.6c-0.48V=0.8c-V for V=0.2c/0.52=0.3846.


Rocket A moves to the right at 0.3846c relative to rocket B and rocket B moves to the left at 0.3846c relative to rocket A and with the centre of mass moving at 0.3846c towards the right.


Tony B.



Hi April!

The X' refers to coordinate systems and not to any calculus. There is no calculus in this post, except as basic differential and the difference between two measurements.

Two events, say the sending and receiving of a signal are measured in TWO reference systems O and O' say with reference frame O moving with velocity v relative to reference frame O' or vice versa.

Much confusion then arises in failing to properly define the coordinates in a manner of 'who moves relative to what'.

So, a 'proper time' can be defined in either sysyem; 'proper' meaning that the events coincide in whatever reference frame thus defined - they have the same locality and the measurements are taken at the same place. Then relative to that frame an 'improper' time results in the quandaries (or illogicalities wrt common sense) of Special Relativity. The 'improper' time is measured at different places.

So in the example both April's time and Mac's time can be the 'proper' time and be 'dilated' relative to the other under the coordinate definitions.

But this is used technically to define instantenuity and simultaneity in the Lorentz formulas, which I tried to derive from a more simple premise, using the geometric mean of differentials.

Tony B.


The Rising of the Sun, The Running of the Deer

The holly and the ivy,
When they are both full grown,
Of all trees that are in the wood,
The holly bears the crown

Yuletide Carol from Druidic Origins

{Jordan Stratford, 21.12.2004}

H)e(S)e(H)=TwinSoul=GoDoG=DoGoD
LIAFAIL=50=CIRCLE=PACIFICAP=64=8x8=ISRAEL=EXODUS.3.14
YaHWHeY=95=Excalibur=IAMTHATIAM=Scorpio=Neptune=59=DRAGON
Tony 104 of a native Indian emblem of the Running Deer!!!




To: Panentheism@yahoogroups.com
From: april0203@aol.com
Date: Tue, 1 Jan 2008 20:12:47 -0500
Subject: Re: [Panentheism] April, Mac and John test the relativity of time

Thank you so much, Tony, for taking the time to try and help by writing this up. I've read it, but I'll have to humbly admit that I'll need some time to absorb it, though the math looks mostly algebraic with some beginning calculus (i.e. "x prime").

I'll try and spend more time on it later.

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Didymos

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Re: Can You Remember How You Did It? - Andromedean Transmissions!

Post  Didymos on Sat Oct 27, 2012 11:38 am

mudra wrote:
SpiralOut wrote:

"A second, standalone reference to the year 2012 has been discovered. Although this 2012 brick, or, “Comalcalco Brick” as it’s called was discovered several years ago, it has been kept a closely-guarded secret by Mexican authorities and archeologists–this brick is separate entirely from the Mayan Long Count Calendar, and the implications of this archeological record are astounding. Why was it kept a secret until now? Surely archeologists know of the multitude of concerned people who know enough of the truth and the ever-increasing difficulty in hiding the facts that are coming to light before the year 2012, so if they wanted to spread disinformation surely they would have benefited by releasing it earlier than waiting all the way until now.

This 2012 brick is a wholly separate record by the ancient Mayans, mentioning the year 2012 concretely, and specifically, and was carved in stone solely for this reason. This is the single most important discovery regarding the ancient Mayan 2012 prophecies, and this brick which warns of the catastrophes to befall Earth in 2012 was made years after the Long Count Calendar, as a reinforcement to what they believed.

The date inscribed on the brick coincide with the end of the 13th Baktun, which falls exactly on December 21, 2012. Archeologists and Mexican authorities are downplaying this finding, but they do admit that it is indeed a direct reference to the sacred date. They are not denying this fact; they can’t!

Most interestingly, the third glyph (line) on the 2012 brick reads as ‘huli’, meaning “he/she/it arrives”. That much is clear, though a crack in the Tortuguero stone partially obscures this glyph, which archeologists interpret as: “He will descend from the sky.” Is this a reference to Nibiru, or Planet X? Or possibly a coincidence with Biblical prophecy? These two findings, along with the ancient Mayan calendar make for some very profound events to unfold soon, are we to take seriously the things we find. We’d be very foolish not to."



Who is going to arrive?

Thank you SpiralOut. I think I read this too somewhere.
Do you have the link to the article you are refering to ?
Thanks.

Love from me
mudra

mudra wrote:
SpiralOut wrote:I would love to mudra, but unfortunately I can't post links for 7 more days. :/

Oh yes I had totally forgotten about this . Silly forum rules.
Sorry about the inconvenience.
Well we will have to be patient then ;)

Love for you

mudra



mudra wrote:2012 Mayan Prophecy Solar Flare Long Count Alignment

http://www.youtube.com/watch?v=UzwQ4-sPjIs


Love Always
mudra



mudra wrote:Mayans demand an end to 2012 doomsday myth

October 24, 2012


GUATEMALA CITY — Guatemala’s Mayan people accused the government and tour groups on Wednesday of perpetuating the myth that their calendar foresees the imminent end of the world for monetary gain.

“We are speaking out against deceit, lies and twisting of the truth, and turning us into folklore-for-profit. They are not telling the truth about time cycles,” charged Felipe Gomez, leader of the Maya alliance Oxlaljuj Ajpop.

Several films and documentaries have promoted the idea that the ancient Mayan calendar predicts that doomsday is less than two months away, on December 21, 2012.


The Culture Ministry is hosting a massive event in Guatemala City — which as many as 90,000 people are expected to attend — just in case the world actually does end, while tour groups are promoting doomsday-themed getaways.

Maya leader Gomez urged the Tourism Institute to rethink the doomsday celebration, which he criticized as a “show” that was disrespectful to Mayan culture.

Experts say that for the Maya, all that ends in 2012 is one of their calendar cycles, not the world.


read on: http://www.rawstory.com/rs/2012/10/24/mayan-demand-an-end-to-2012-doomsday-myth/

Love Always
mudra

Who will arrive? Bolon Yokte of course, also known under many other names and labels, including the 'Office of the Cosmic LogosTwin'. However hisher arrival can and will be felt by some in the invisbility it harbours as the 'thief of the night', 'reconfiscating' a misappropriated 'Kingdom of the Big Shebang!'

There will be no planetary 'gravitational-geometric' alignment blocking out the sunlight or any such physical phenomenon, as presented in the video shared by Mudra.
The Sun, as the central focus of the local star system as the focal star Rahsol will however experience a 'data upload' sometime on Friday, December 21st, 2012 and so 8 minutes following a metaphysical 'pole reversal' of the 4-dimensional space, which embeds the 3-dimensional space of the measurable and observable innermost geometrical 'center of gravity' and 'center of mass' of the extended planetary identity.
This is physically defined as a 'Noosphere' or 'Akashic Bubble' in a metaphysical connotation for a astrophysical definition of a 'Lagrangian Hill Sphere', also embracing the 'consciousness evolution' of the Gaean history of so 4.6 billion years and extends like a cocoon to a distance of about 2 million kilometers from this planetary center. This 'Cosmic Ovum' so encompasses the physical presence and definition of the Moon as Earth's satellite and extends so 5% to the planet Venus, but does not engage any other physicalized object in the local star- or solar system, except in orbital intersections.

The physicality of any 2012-event relates to the incoming gamma ray signal-wave from Sagittarius A*, aka the Black Hole-White Hole source-sink at the center of the Milky Way host galaxy, known as Hunab Ku to the Mayans. The 'path' or journey of this galactic wave is called Kuxan Suum aka 'The Way to the Center of the Universe' by the Maya and describes the 'Street of the Rebuilding of the Temple' in particular scriptures (Daniel.9.24-27) and also the 'Journey Home' in certain 'channelings', say as represented by the 'The Voyage Home' Star Trek film of 1986.



Dragons can read between the lines in this message and in the code of Armageddon = Dragon Made = 82=41+41 = Dream Maerd = Mad Dream 23 = Dream In Dam.






2 Peter 3:9-11
King James Version (KJV)

9 The Lord is not slack concerning his promise, as some men count slackness; but is longsuffering to us-ward, not willing that any should perish, but that all should come to repentance.
10 But the day of the Lord will come as a thief in the night; in the which the heavens shall pass away with a great noise, and the elements shall melt with fervent heat, the earth also and the works that are therein shall be burned up.
11 Seeing then that all these things shall be dissolved, what manner of persons ought ye to be in all holy conversation and godliness,


Revelation 3:2-4
King James Version (KJV)

2 Be watchful, and strengthen the things which remain, that are ready to die: for I have not found thy works perfect before God.
3 Remember therefore how thou hast received and heard, and hold fast, and repent. If therefore thou shalt not watch, I will come on thee as a thief, and thou shalt not know what hour I will come upon thee.
4 Thou hast a few names even in Sardis which have not defiled their garments; and they shall walk with me in white: for they are worthy.

Revelation 16:14-16
King James Version (KJV)

14 For they are the spirits of devils, working miracles, which go forth unto the kings of the earth and of the whole world, to gather them to the battle of that great day of God Almighty.
15 Behold, I come as a thief. Blessed is he that watcheth, and keepeth his garments, lest he walk naked, and they see his shame.
16 And he gathered them together into a place called in the Hebrew tongue Armageddon.


Q.E.F.Q.E.D

Q.E.F. = Quod Erat Faciendum.............Raven de Lion de Draconis de Thuban.............Quod Erat Demonstrandum = Q.E.D.

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